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Messages 11448 - 11477 of 16968   Oldest  |  < Older  |  Newer >  |  Newest
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11448
Dear Alexey and Jean-Pierre [AM] ... BC ... not on ... measures in the ... constructing ... [JPE] ... the ... signed. ... such ... when ... means ... another...
ndergiades
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Aug 2, 2005
6:18 pm
11449
... From: Milorad Stevanovic To: hyacinthos@yahoogroups.com Sent: Saturday, July 30, 2005 1:02 PM Subject: Inscribed triangle homothetic to inner Morley...
Milorad Stevanovic
yumarince
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Aug 3, 2005
6:53 pm
11450
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2005volume5/FG200515index.html The editors, Forum...
ForumGeom
ForumGeom@...
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Aug 3, 2005
7:54 pm
11451
Dear Hyacintheans; Recently, I have been working on the Fuhrmann triangle and I have a generalization to which I give a synthethic proof (I really don't know...
KHOA LU
treegoner
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Aug 7, 2005
5:13 am
11452
Hello to all from a long absence, As The Triangle Book is taking a long time to write, I will begin posting some pictures of topics in the book on my web site....
Steve Sigur
steve_sigur
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Aug 8, 2005
5:23 pm
11453
Dear friends of Hyacinthos: A beautiful problem: Let ABC be a triangle, and draw isosceles triangles BCD;CAE;ABF externally to ABC, with BC;CA;AB as their...
Ricardo Barroso
ricardobca
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Aug 13, 2005
11:07 am
11454
Dear Riccardo ... If D,E,F lie respectively on the perpendicular bisectors of BC, CA, AB, obviously DEF and ABC are orthologic at O; hence your three lines ...
jpehrmfr
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Aug 13, 2005
11:29 am
11455
Dear friends, Let A'B'C' be the cevian triangle of the incenter I and let A"B"C" be its pedal triangle (intouch triangle) Let A* be the circumcenter of B'C'I...
Eric Danneels
efn4900
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Aug 15, 2005
2:58 pm
11456
Dear Eric, ... your locus is the union of : -- the line at infinity, -- a circular quintic without known (to me) centers on it, -- a circular circum-octic...
Bernard Gibert
bernardgibert
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Aug 15, 2005
3:24 pm
11457
Dear Bernard, Please...what tool do you use to disect such problems? Sincerely, Jeff Brooks ... cyclic...
Jeff Brooks
jbrooks_tulsa
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Aug 17, 2005
5:55 am
11458
Dear Hyacinthos, I need a little help. If there is a triangle ABC with centroid G, how can I construct a circumhyperbola which center has a minimum distance ...
ninaxiceph
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Aug 17, 2005
7:37 am
11459
Dear Richard ... The nature of a circumconic with center W depends on the position of W wrt the sidelines of the medial triangle. If W0 is the projection of G...
jpehrmfr
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Aug 17, 2005
9:05 am
11460
Dear Jean-Pierre ... I don't know, is the distance between W0 and G the minimal possible distance from G to circumhyperbola's center W? Am I right? How can I...
ninaxiceph
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Aug 17, 2005
11:30 am
11461
Dear Hyacinthists, In Crux Vol. 13 (1987), p.153 there is a final comment to the problem in question (construct a triangle given HPO such that P belongs to the...
Luís Lopes
qedtexte
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Aug 18, 2005
1:34 am
11462
... Dear Jeff: I have seen your question to Bernard about the tool to dissect this kind of questions. I have write a notebook of Mathematica, Baricentricas.nb,...
garciacapitan
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Aug 18, 2005
7:36 am
11463
... Dear Jeff: I have seen your question to Bernard about the tool to dissect this kind of questions. I have write a notebook of Mathematica, Baricentricas.nb,...
garciacapitan
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Aug 18, 2005
7:37 am
11464
Dear friends, Obviously, 3) and 4) below represent the same configuration. The relationship with 1) is perhaps more interesting. It seems the circumcevian...
Jeff Brooks
jbrooks_tulsa
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Aug 21, 2005
8:09 am
11465
Let ABC be a triangle. Denote A1 = (Reflection of BC in AB) /\ (Reflection of BC in AC). B1 = (Reflection of CA in BC) /\ (Reflection of CA in BA) C1 =...
Antreas P. Hatzipolakis
xpolakis
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Aug 22, 2005
12:45 pm
11466
Hello Antreas, A very nice problem. But, the circles do not appear to concur here. Sincerely, Jeff [APH]...
Jeff Brooks
jbrooks_tulsa
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Aug 23, 2005
6:42 am
11467
Dear Hyacinthos, Here's an interesting problem. It is easy to find a Heronian triangle that may be dissected into 3 Heronian triangles. But: is there a...
zbaruh
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Aug 23, 2005
5:04 pm
11468
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2005volume5/FG200516index.html The editors Forum...
ForumGeom
ForumGeom@...
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Aug 23, 2005
8:51 pm
11469
Dear Antreas & Jeff, [APH] ... I think so as well, concurrence at your trilinear, {Sin[2^n A] / Sin[(2^n - 1) A] ::} Trilinear center of circle AnBC = {Cot[2^n...
peter_mows
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Aug 24, 2005
2:25 pm
11470
Dear Peter ... Thanks for these results. In old problem discussions, you investigated variations with excentral etc triangles. So here, if AxBxCx is the...
Antreas P. Hatzipolakis
xpolakis
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Aug 24, 2005
4:21 pm
11471
In a triangle: cot(A/2) = (sinB + sinC) / (cosB + cosC) Here is a proof with trilinears. Lemma: Let ABC be a triangle, P = (x:y:z) in *actual* trilinears, and...
Antreas P. Hatzipolakis
xpolakis
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Aug 24, 2005
5:25 pm
11472
... every n. ... A]}. ... [APH] ... The circumcircle of the centers of the 3 circles AnBC, ABnC ABCn pass through the point of concurrence for n+1 It does...
peter_mows
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Aug 25, 2005
11:55 am
11473
Dear Peter ... How about the variation? A'1 := (Reflection of AoBo in BoCo) /\ (Reflection of AoCo in BoCo) Similarly B'1, C'1. Are the triangles ABC,...
Antreas P. Hatzipolakis
xpolakis
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Aug 25, 2005
2:30 pm
11474
Dear Jeff ... a ... on ... Construction of A' (cyclically for B', C') T = second intersection of the line BQ with the circle CPQ T'= second intersection of the...
jpehrmfr
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Aug 25, 2005
4:15 pm
11475
Dear Antreas, [APH] ... Yes, at X(186), trilinear Sin[3 A] / (Cos[A] Sin[A]) :: Reckon that circles A'1BC, AB'1C, ABC'1 concurr at X(1263). Best regards, ...
peter_mows
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Aug 25, 2005
6:24 pm
11476
Dear Jeff ... the ... with ... then ... particular ... a ... In my previous mail, I've noticed that A' = CT inter BT' where T is second intersection of the...
jpehrmfr
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Aug 25, 2005
11:34 pm
11477
Dear Jean-Pierre, Thank you very much for your results in message 11474. I never noticed the construction you gave for triangle A'B'C' or the complex ...
Jeff Brooks
jbrooks_tulsa
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Aug 26, 2005
1:10 am
Messages 11448 - 11477 of 16968   Oldest  |  < Older  |  Newer >  |  Newest
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